document.write( "Question 512113: Lisa left camp on her bike at noon and rode at an avg rate of 10mph. Morton left in his van at 1;30pm traveling 35mph. how long till morton catches up with lisa? \n" ); document.write( "

Algebra.Com's Answer #342527 by josmiceli(19441) $\"\"$ $\"About$

You can put this solution on YOUR website!
First find Lisa's head start in miles
\n" ); document.write( " $\"+10%2A1.5+=+15+\"$ mi ( note that 1.5 is time from noon to 1:30 )
\n" ); document.write( "Let $\"+d+\"$ = distance Morton has to go to catch Lisa
\n" ); document.write( "Let $\"+t+\"$ = time from when Morton
\n" ); document.write( "leaves to when he catches Lisa
\n" ); document.write( "-----------------
\n" ); document.write( "given:
\n" ); document.write( "Morton:
\n" ); document.write( "(1) $\"+d+=+35t+\"$
\n" ); document.write( "Lisa:
\n" ); document.write( "(2) $\"+d+-+15+=+10t+\"$
\n" ); document.write( "----------------
\n" ); document.write( "substitute (1) in (2)
\n" ); document.write( "(2) $\"+35t+-+15+=+10t%0D%0A%282%29+%7B%7B%7B+25t+=+15+\"$
\n" ); document.write( "(2) $\"+t+=+.6+\"$ hr
\n" ); document.write( " $\"+.6%2A60+=+36+\"$ min
\n" ); document.write( "Morton catches Lisa in 36 min, or at 2:06 PM
\n" ); document.write( "check:
\n" ); document.write( "(1) $\"+d+=+35t+\"$
\n" ); document.write( "(1) $\"+d+=+35%2A.6+\"$
\n" ); document.write( "(1) $\"+d+=+21+\"$ mi
\n" ); document.write( "and
\n" ); document.write( "(2) $\"+d+-+15+=+10t+\"$
\n" ); document.write( "(2) $\"+d+-+15+=+10%2A.6+\"$
\n" ); document.write( "(2) $\"+d+=+15+%2B+6+\"$
\n" ); document.write( "(2) $\"+d+=+21+\"$ mi
\n" ); document.write( "OK \n" ); document.write( "

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