document.write( "Question 512082: In a collection of nickels, dimes, and quarters, there are twice as many dimes as nickels and 3 fewer quarters than dimes. If the total value of the coins is $4.50, how many of each type of coin are there? \n" ); document.write( "

Algebra.Com's Answer #342525 by oberobic(2304) $\"\"$ $\"About$

You can put this solution on YOUR website!
With money problems you have to keep track of the counts and the values.
\n" ); document.write( "n = number of nickels
\n" ); document.write( "5n = value of nickels in cents
\n" ); document.write( "d = number of dimes
\n" ); document.write( "10d = value of dimes in cents
\n" ); document.write( "q = number of quarters
\n" ); document.write( "25q = value of quarters in cents
\n" ); document.write( ".
\n" ); document.write( "5n + 10d + 25q = 450 cents
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\n" ); document.write( "d = 2n
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\n" ); document.write( "q = d-3
\n" ); document.write( "q = 2n -3
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\n" ); document.write( "substitute
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\n" ); document.write( "5n + 10(2n) + 25(2n-3) = 450
\n" ); document.write( ".
\n" ); document.write( "5n + 20n + 50n -75 = 450
\n" ); document.write( "75n = 525
\n" ); document.write( "n = 7
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\n" ); document.write( "d = 14
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\n" ); document.write( "q = 11
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\n" ); document.write( "5*7 = 35 cents
\n" ); document.write( "10*14 = 140 cents
\n" ); document.write( "25*11 = 275 cents
\n" ); document.write( "35+140+275 = 450 cents
\n" ); document.write( ".
\n" ); document.write( "Answer: 7 nickels, 14 dimes, and 11 quarters.
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\n" ); document.write( "Done.
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