document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=512072>Question 512072</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Not sure how to solve this problem on my daughters homework. I would like to understand so I can attempt to explain it to her. Here it is.. The difference of two numbers is 8. The first number x is 1 less than twice the second number y. Write and solve a system of linear equations to find the two numbers </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #342520 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=342520\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> \"The first number x is 1 less than twice the second number y\" ___ x = 2y -1\r<BR>\n" );
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document.write( "\"The difference of two numbers is 8\" ___ x - y = 8\r<BR>\n" );
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document.write( "substituting the equivalent value for x from the 1st equation ___ (2y - 1) - y = 8<BR>\n" );
document.write( "___ y = 9\r<BR>\n" );
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document.write( "substituting into the 2nd equation ___ x - (9) = 8<BR>\n" );
document.write( "___ x = 17 </SPAN>\n" );
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