document.write( "Question 51310: When using the quadratic formula to solve a quadratic equation (ax2 + bx + c = 0), the discriminant is b2 - 4ac. This discriminant can be positive, zero, or negative.\r
\n" ); document.write( "\n" ); document.write( "Create three unique equations where the discriminant is positive, zero, or negative. For each case, explain what this value means to the graph of y = ax2 + bx + c. \r
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Algebra.Com's Answer #34248 by rapaljer(4671)\"\" \"About 
You can put this solution on YOUR website!
Notice the THREE parts to this solution:\r
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\n" ); document.write( "CASE I:
\n" ); document.write( "Discriminant is positive: \"x%5E2-4+=0\"
\n" ); document.write( "There are TWO real solutions. The implication for the graph of \"y=x%5E2+-4\" is that the graph crosses the x axis at TWO points.
\n" ); document.write( "\"graph%28300%2C300%2C-6%2C6%2C-6%2C6%2Cx%5E2-4%29\"\r
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\n" ); document.write( "CASE II:
\n" ); document.write( "Discriminant is zero: \"x%5E2-4x%2B4+=0\"
\n" ); document.write( "There is ONLY ONE real solution. The implication for the graph of \"y=x%5E2+-4x%2B4\" is that the graph touches the x axis at only one point, but it does NOT cross the x axis.
\n" ); document.write( "\"graph%28300%2C300%2C-6%2C6%2C-6%2C6%2Cx%5E2-4x%2B4%29\"\r
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\n" ); document.write( "CASE III:
\n" ); document.write( "Discriminant is negative: \"x%5E2%2B4+=0\"
\n" ); document.write( "There are NO real solutions. The implication for the graph of \"y=x%5E2+%2B4\" is that the graph never touches nor crosses the x axis.
\n" ); document.write( "\"graph%28300%2C300%2C-6%2C6%2C-6%2C6%2Cx%5E2%2B4%29\"\r
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\n" ); document.write( "\n" ); document.write( "This is a VERY important concept, especially with graphing calculators!! Congratulations on an excellent question!!\r
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\n" ); document.write( "\n" ); document.write( "R^2 at SCC
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