document.write( "Question 512012: Lem runs 10 mps. Uel runs 6 mps. With a 50 m head start for Uel, how long will it take Lem to catch up with Uel? \n" ); document.write( "
Algebra.Com's Answer #342476 by josmiceli(19441)\"\" \"About 
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Let \"d\" = distance Lem has to go
\n" ); document.write( "\"+d+-+50+\" = distance Uel has to go
\n" ); document.write( "Let \"+t\" = time that it takes Lem to catch Uel
\n" ); document.write( "given:
\n" ); document.write( "For Uel:
\n" ); document.write( "(1) \"+d+-+50+=+6t+\"
\n" ); document.write( "For Lem:
\n" ); document.write( "(2) \"+d+=+10t+\"
\n" ); document.write( "-------------
\n" ); document.write( "Substitute (2) into (1)
\n" ); document.write( "(1) \"+10t+-+50+=+6t+\"
\n" ); document.write( "(1) \"+4t+=+50+\"
\n" ); document.write( "(1) \"+t+=+12.5+\" sec
\n" ); document.write( "check:
\n" ); document.write( "(1) \"+d+-+50+=+6%2A12.5+\"
\n" ); document.write( "(1) \"+d+-+50+=+75++\"
\n" ); document.write( "(1) \"+d+=+125+\" m
\n" ); document.write( "and
\n" ); document.write( "(2) \"+d+=+10%2A12.5+\"
\n" ); document.write( "(2) \"+d+=+125+\" m
\n" ); document.write( "OK
\n" ); document.write( "
\n" );