document.write( "Question 511994: a twin engine aircraft can fly 720 miles from a city \"a\" to a city \"b\" in 4 hours with the wind and make a return in 6 hours against the wind. what is the speed of the wind? \n" ); document.write( "
Algebra.Com's Answer #342473 by oberobic(2304)![]() ![]() ![]() You can put this solution on YOUR website! d = r*t is the fundamental distance equation. \n" ); document.write( ". \n" ); document.write( "Fly to B: \n" ); document.write( "r = airspeed + wind speed = (a + w) mph \n" ); document.write( "t = 4 hr \n" ); document.write( "d = 720 mi \n" ); document.write( ". \n" ); document.write( "Return to A: \n" ); document.write( "r= airspeed -wind speed = (a - w) mph \n" ); document.write( "t = 6 hr \n" ); document.write( "d = 720 mi \n" ); document.write( ". \n" ); document.write( "6a - 6w = 720 \n" ); document.write( "4a + 4w = 720 \n" ); document.write( ". \n" ); document.write( "12a - 12w = 1440 \n" ); document.write( "12a + 12w = 2160 \n" ); document.write( "----------------- \n" ); document.write( "0a -24w = -720 \n" ); document.write( ". \n" ); document.write( "w = 30 = wind speed \n" ); document.write( ". \n" ); document.write( "substitute w=30 to find airspeed \n" ); document.write( ". \n" ); document.write( "6a - 6(30) = 720 \n" ); document.write( "6a = 720 + 180 \n" ); document.write( "6a = 900 \n" ); document.write( ". \n" ); document.write( "a = 150 = airspeed \n" ); document.write( ". \n" ); document.write( "Check to see if it can cover the distances in the correct times. \n" ); document.write( ". \n" ); document.write( "(150-30)*6 = ?? \n" ); document.write( "120*6 = 720 \n" ); document.write( "correct \n" ); document.write( ". \n" ); document.write( "(150+30)*4 = ?? \n" ); document.write( "(180)*4 = 720 \n" ); document.write( "correct \n" ); document.write( ". \n" ); document.write( "Answer: The wind speed is 30 mph. \n" ); document.write( ". \n" ); document.write( "Done. \n" ); document.write( " |