document.write( "Question 511994: a twin engine aircraft can fly 720 miles from a city \"a\" to a city \"b\" in 4 hours with the wind and make a return in 6 hours against the wind. what is the speed of the wind? \n" ); document.write( "
Algebra.Com's Answer #342473 by oberobic(2304)\"\" \"About 
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d = r*t is the fundamental distance equation.
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\n" ); document.write( "Fly to B:
\n" ); document.write( "r = airspeed + wind speed = (a + w) mph
\n" ); document.write( "t = 4 hr
\n" ); document.write( "d = 720 mi
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\n" ); document.write( "Return to A:
\n" ); document.write( "r= airspeed -wind speed = (a - w) mph
\n" ); document.write( "t = 6 hr
\n" ); document.write( "d = 720 mi
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\n" ); document.write( "6a - 6w = 720
\n" ); document.write( "4a + 4w = 720
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\n" ); document.write( "12a - 12w = 1440
\n" ); document.write( "12a + 12w = 2160
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\n" ); document.write( "0a -24w = -720
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\n" ); document.write( "w = 30 = wind speed
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\n" ); document.write( "substitute w=30 to find airspeed
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\n" ); document.write( "6a - 6(30) = 720
\n" ); document.write( "6a = 720 + 180
\n" ); document.write( "6a = 900
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\n" ); document.write( "a = 150 = airspeed
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\n" ); document.write( "Check to see if it can cover the distances in the correct times.
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\n" ); document.write( "(150-30)*6 = ??
\n" ); document.write( "120*6 = 720
\n" ); document.write( "correct
\n" ); document.write( ".
\n" ); document.write( "(150+30)*4 = ??
\n" ); document.write( "(180)*4 = 720
\n" ); document.write( "correct
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\n" ); document.write( "Answer: The wind speed is 30 mph.
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\n" ); document.write( "Done.
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