document.write( "Question 511931: How many liters of a mixture containing 70% alcohol should be added to a mixture containing 20% alcohol to obtain 16 liters of a mixture containing 50% alcohol? \n" ); document.write( "
Algebra.Com's Answer #342457 by nerdybill(7384)![]() ![]() You can put this solution on YOUR website! How many liters of a mixture containing 70% alcohol should be added to a mixture containing 20% alcohol to obtain 16 liters of a mixture containing 50% alcohol? \n" ); document.write( ". \n" ); document.write( "Let x = amount (liters) of 70% alcohol \n" ); document.write( "then \n" ); document.write( "16-x = amount (liters) of 20% alcohol \n" ); document.write( ". \n" ); document.write( ".70x + .20(16-x) = .50(16) \n" ); document.write( ".70x + 3.2-.20x = 8 \n" ); document.write( ".50x + 3.2 = 8 \n" ); document.write( ".50x = 4.8 \n" ); document.write( "x = 9.6 liters (70% alcohol) \n" ); document.write( ". \n" ); document.write( "20% alcohol: \n" ); document.write( "16-x = 16-9.6 = 6.4 liters\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |