document.write( "Question 511931: How many liters of a mixture containing 70% alcohol should be added to a mixture containing 20% alcohol to obtain 16 liters of a mixture containing 50% alcohol? \n" ); document.write( "
Algebra.Com's Answer #342457 by nerdybill(7384)\"\" \"About 
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How many liters of a mixture containing 70% alcohol should be added to a mixture containing 20% alcohol to obtain 16 liters of a mixture containing 50% alcohol?
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\n" ); document.write( "Let x = amount (liters) of 70% alcohol
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\n" ); document.write( "16-x = amount (liters) of 20% alcohol
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\n" ); document.write( ".70x + .20(16-x) = .50(16)
\n" ); document.write( ".70x + 3.2-.20x = 8
\n" ); document.write( ".50x + 3.2 = 8
\n" ); document.write( ".50x = 4.8
\n" ); document.write( "x = 9.6 liters (70% alcohol)
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\n" ); document.write( "20% alcohol:
\n" ); document.write( "16-x = 16-9.6 = 6.4 liters\r
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