document.write( "Question 511829: The measure of the supplement of an angle is 40 more than 2 times the measure of the compliment of the angle. Find the measure of the angle\r
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\n" ); document.write( "\n" ); document.write( "Here is what i have tried so far \r
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\n" ); document.write( "\n" ); document.write( "90-x = compliment of angle
\n" ); document.write( "180-x =suppliment of angle \r
\n" ); document.write( "\n" ); document.write( "180-x= 2(90-x)+40
\n" ); document.write( "180-x=180-2x+40
\n" ); document.write( "180-x=220-2x
\n" ); document.write( "180+2x=110\r
\n" ); document.write( "\n" ); document.write( "2x=55\r
\n" ); document.write( "\n" ); document.write( "I think my set up is wrong could u please show me the correct set up and answer
\n" ); document.write( "thank you\r
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Algebra.Com's Answer #342421 by John10(297)\"\" \"About 
You can put this solution on YOUR website!
Your setup is 100% CORRECT:)
\n" ); document.write( "However you did wrong right here:
\n" ); document.write( "180 - x = 220 - 2x
\n" ); document.write( "2x - x = 220 - 180
\n" ); document.write( "x = 40 is what you needed.
\n" ); document.write( "Check:\r
\n" ); document.write( "\n" ); document.write( "180 - 40 = 2(90 - 40) + 40
\n" ); document.write( "140 = 2(50) + 40
\n" ); document.write( "140 = 100 + 40
\n" ); document.write( "140 = 140 (checked)
\n" ); document.write( "John10:)
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