document.write( "Question 511829: The measure of the supplement of an angle is 40 more than 2 times the measure of the compliment of the angle. Find the measure of the angle\r
\n" );
document.write( "
\n" );
document.write( "\n" );
document.write( "Here is what i have tried so far \r
\n" );
document.write( "
\n" );
document.write( "\n" );
document.write( "90-x = compliment of angle
\n" );
document.write( "180-x =suppliment of angle \r
\n" );
document.write( "\n" );
document.write( "180-x= 2(90-x)+40
\n" );
document.write( "180-x=180-2x+40
\n" );
document.write( "180-x=220-2x
\n" );
document.write( "180+2x=110\r
\n" );
document.write( "\n" );
document.write( "2x=55\r
\n" );
document.write( "\n" );
document.write( "I think my set up is wrong could u please show me the correct set up and answer
\n" );
document.write( "thank you\r
\n" );
document.write( "
\n" );
document.write( "
\n" );
document.write( "\n" );
document.write( " \n" );
document.write( "
Algebra.Com's Answer #342421 by John10(297)![]() ![]() You can put this solution on YOUR website! Your setup is 100% CORRECT:) \n" ); document.write( "However you did wrong right here: \n" ); document.write( "180 - x = 220 - 2x \n" ); document.write( "2x - x = 220 - 180 \n" ); document.write( "x = 40 is what you needed. \n" ); document.write( "Check:\r \n" ); document.write( "\n" ); document.write( "180 - 40 = 2(90 - 40) + 40 \n" ); document.write( "140 = 2(50) + 40 \n" ); document.write( "140 = 100 + 40 \n" ); document.write( "140 = 140 (checked) \n" ); document.write( "John10:) \n" ); document.write( " |