document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=511788>Question 511788</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 1/(x+1) + a/(x^2-1) = x/(x^2-1) to hold for all x, a must equal a # <BR>\n" );
document.write( "simplify the left side of the equation and compare what you get with the right side.\r<BR>\n" );
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document.write( "(1/(x+1))(x^2-1)/(x^2-1) + (a/(x^2-1))(x+1)/(x+1)= (x^2-1)+a(x+1)/((x^2-1)(x+1))<BR>\n" );
document.write( "therefore (ax+a)/(x^3-x) which simplifies to a/(x(x-1))\r<BR>\n" );
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document.write( "but this is not a number... let me know! thanks! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #342401 by </B><A HREF=/tutors/aboutme.mpl?userid=John10><B>John10(297)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=John10><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=John10><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=342401\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Okay.. your equation is like below:<BR>\n" );
document.write( "1/(x + 1) + a/(x^2 - 1) = x/(x^2 - 1)<BR>\n" );
document.write( "You know that the LCD is x^2 - 1 = (x - 1)(x + 1)<BR>\n" );
document.write( "You multiply both sides by LCD and simplify, you will have the below statement:<BR>\n" );
document.write( "1(x - 1) + a = x<BR>\n" );
document.write( "x - 1 + a =x<BR>\n" );
document.write( "Subtract x from both sides:<BR>\n" );
document.write( "x - x - 1 + a = x - x<BR>\n" );
document.write( "-1 + a = 0<BR>\n" );
document.write( "a = 1 which is what you are looking for.<BR>\n" );
document.write( "John10:) </SPAN>\n" );
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