document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=511713>Question 511713</A>: <I><SPAN STYLE=\"word-break: break-all;\"> There are one hundred fifty coins, all in 25 cents and 50 cents. If the number of 25 cent coins is ten more than three times the number of 50 cents, find the number of each kind of coin </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #342380 by </B><A HREF=/tutors/aboutme.mpl?userid=SUNIL1987MAURYA><B>SUNIL1987MAURYA(7)</B></A><img src=\"/images/stars/stars-05.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=SUNIL1987MAURYA><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=SUNIL1987MAURYA><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=342380\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let no. of 50 cents coin be x<BR>\n" );
document.write( "then no. of 25 cents coin=3*x+10<BR>\n" );
document.write( "so<BR>\n" );
document.write( "x+3*x+10=150<BR>\n" );
document.write( "4*x=150-10<BR>\n" );
document.write( "x=140/4<BR>\n" );
document.write( "x=35<BR>\n" );
document.write( "therefore<BR>\n" );
document.write( "no. of 50 cents coin=35<BR>\n" );
document.write( "& no. of 25 cents coin=35*3+10=115 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );