document.write( "Question 511706: A 150 metres long train crosses a man walking at the speed of 6km/h in the opposite direction in 6 seconds. The speed of the train in km/h is how much? \n" ); document.write( "

Algebra.Com's Answer #342372 by stanbon(75887) $\"\"$ $\"About$

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A 150 metres long train crosses a man walking at the speed of 6km/h in the opposite direction in 6 seconds. The speed of the train in km/h is how much?
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\n" ); document.write( "Let \"r\" be the speed of the train.
\n" ); document.write( "rate = distance/time
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\n" ); document.write( "train rate (r km/hr)= r(km/hr)(1000 m/km)(hr/3600sec) = (r/3.6)(m/sec)
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\n" ); document.write( "man rate: 6(km/hr) = 6(1000/3600) = 6/3.6 = (1/0.6)(m/sec)
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\n" ); document.write( "Train distance in 6 sec = time*rate = 6(r/3.6) = r/0.6 meters
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\n" ); document.write( "Man distance in 6 sec = time*rate = 6(1/0.6) = 1/0.1 = 10 meters
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\n" ); document.write( "Equation:
\n" ); document.write( "train distance - man distance = 150 meters
\n" ); document.write( "(r/0.6) - 10 = 150
\n" ); document.write( "(r/0.6) = 140
\n" ); document.write( "r = 84 meters/sec
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H. \n" ); document.write( "

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