document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=511718>Question 511718</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the measures of the angles of an isosceles triangle if the measure of the vertex angle is 40 degrees las than the sum of the measures of the base angles. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #342370 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=342370\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">     Find the measures of the angles of an isosceles triangle if the measure of the vertex angle is 40 degrees las than the sum of the measures of the base angles.<BR>\n" );
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document.write( "Let x = base angles<BR>\n" );
document.write( "then<BR>\n" );
document.write( "2x-40 = vertex angle<BR>\n" );
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document.write( "2x + (2x-40) = 180<BR>\n" );
document.write( "4x-40 = 180<BR>\n" );
document.write( "4x = 220<BR>\n" );
document.write( "x = 55 degrees (base angle)<BR>\n" );
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document.write( "vertex angle:<BR>\n" );
document.write( "2x-40 = 2(55)-40 = 110-40 = 70 degrees<BR>\n" );
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