document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=511559>Question 511559</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve for x<BR>\n" );
document.write( "log base 2 (3x)=log base 2(5x-8) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #342358 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=342358\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Solve for x<BR>\n" );
document.write( "log base 2 (3x)=log base 2(5x-8)<BR>\n" );
document.write( "log2(3x)=log2(5x-8)<BR>\n" );
document.write( "log2(3x)-log2(5x-8)=0<BR>\n" );
document.write( "place under single log<BR>\n" );
document.write( "log2(3x/(5x-8)=0<BR>\n" );
document.write( "convert to exponential form: base(2) raised to log of number(0)=number(3x/(5x-8)<BR>\n" );
document.write( "2^0=(3x/(5x-8)=1<BR>\n" );
document.write( "3x=5x-8<BR>\n" );
document.write( "2x=8<BR>\n" );
document.write( "x=4 </SPAN>\n" );
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