document.write( "Question 511583: Please help me solve this equation:
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document.write( "What is the standard form of the equation of the line that is perpendicular to 6x+5y=9 and contains (-6,-1) \n" );
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Algebra.Com's Answer #342340 by Maths68(1474)![]() ![]() You can put this solution on YOUR website! Standard Form of Equation of the line: \n" ); document.write( "y=mx+b\r \n" ); document.write( "\n" ); document.write( "Given \n" ); document.write( "6x+5y=9 \n" ); document.write( "rearrage the above equation according to the standard form \n" ); document.write( "5y=-6x+9 \n" ); document.write( "5y/5=(-6x+9)/5 \n" ); document.write( "y=(-6/5)x+9/5 \n" ); document.write( "Compare above equation with the standard form equation \n" ); document.write( "m=-6/5 and b=9/5 \n" ); document.write( "Since lines are perpendicular multiplicatin of their slope will be (-1) \n" ); document.write( "So slope of the required line will be (5/6)\r \n" ); document.write( "\n" ); document.write( "Now we have a point(-6,-1) and slope (5/6)of the line we can easily find required lines by putting these values in the equation of the straight line poin-slope form.\r \n" ); document.write( "\n" ); document.write( "m=(y2-y1)/(x2-x1) \n" ); document.write( "5/6=(y-(-1))/(x-(-6)) \n" ); document.write( "5/6=(y+1)/(x+6) \n" ); document.write( "5(x+6)=6(y+1) \n" ); document.write( "5x+30=6y+6 \n" ); document.write( "-6y=6-5x-30 \n" ); document.write( "-6y=-5x-24 \n" ); document.write( "-6y/-6=(-5x+24)/-6 \n" ); document.write( "y=(-5/-6)x+(-24/-6) \n" ); document.write( "y=(5/6)x+4 \n" ); document.write( "The standard form of the equation of the line \n" ); document.write( "y=(5/6)x+4 \n" ); document.write( "that is perpendicular to 6x+5y=9 and contains (-6,-1)\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |