document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=511645>Question 511645</A>: <I><SPAN STYLE=\"word-break: break-all;\"> jeff starts driving at 60 mph from the same point that lauren starts driving 50 mph. they drive in opposite directions and lauren has a half an hour head start. how long will jeff drive before they are 300 miles apart<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #342333 by </B><A HREF=/tutors/aboutme.mpl?userid=oberobic><B>oberobic(2304)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=oberobic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=342333\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> d = rt is the basic distance equation.<BR>\n" );
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document.write( "Lauren's d = 50*t<BR>\n" );
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document.write( "Jeff's d<sub>1</sub> = 60(t - 1/2)<BR>\n" );
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document.write( "d + d<sub>1</sub> = 300<BR>\n" );
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document.write( "50t + 60t - 30 = 300<BR>\n" );
document.write( "110t = 330<BR>\n" );
document.write( "t = 3 hr<BR>\n" );
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document.write( "Check to ensure the distance is 300 miles.<BR>\n" );
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document.write( "Lauren drives 3 hr @ 50 mph = 150 miles.<BR>\n" );
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document.write( "Jeff drives 2.5 hr @ 60 mph = 150 miles.<BR>\n" );
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document.write( "OK.<BR>\n" );
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document.write( "Answer:  Jeff will have driven for 2 1/2 hrs when then are 300 miles apart.<BR>\n" );
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document.write( "Done. </SPAN>\n" );
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