document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=511552>Question 511552</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the length of a rectangle is twice as long as the width and its perimeter is 54 ft. find the dimensions of the rectangle. can you show me the steps. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #342327 by </B><A HREF=/tutors/aboutme.mpl?userid=oberobic><B>oberobic(2304)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=oberobic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=342327\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> L = 2W<BR>\n" );
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document.write( "P = 2(L+W) <BR>\n" );
document.write( "P = 54<BR>\n" );
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document.write( "substitute<BR>\n" );
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document.write( "2(L+W) = 54<BR>\n" );
document.write( "2(2W + W) = 54<BR>\n" );
document.write( "4W +2W = 54<BR>\n" );
document.write( "6W = 54<BR>\n" );
document.write( "W = 9<BR>\n" );
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document.write( "L = 2W<BR>\n" );
document.write( "L = 2(9) = 18<BR>\n" );
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document.write( "Check the perimeter<BR>\n" );
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document.write( "2(18+9) = 2(27) = 54<BR>\n" );
document.write( "Correct.<BR>\n" );
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document.write( "Answer: Length = 18; Width = 9.<BR>\n" );
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document.write( "Done. </SPAN>\n" );
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