document.write( "Question 511387: a number consists of two digits the digits in the ten's place is 3 times the digit in the unit place if 54 is subtracted from the number the digits are reversed . The number is \n" ); document.write( "
Algebra.Com's Answer #342261 by ankor@dixie-net.com(22740)\"\" \"About 
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a number consists of two digits the digits in the ten's place is 3 times the digit in the unit place if 54 is subtracted from the number the digits are reversed.
\n" ); document.write( " The number is
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\n" ); document.write( "Let the two digit number = 10x + y
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\n" ); document.write( "\"the ten's place is 3 times the digit in the unit place\"
\n" ); document.write( "x = 3y
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\n" ); document.write( "\"if 54 is subtracted from the number the digits are reversed.\"
\n" ); document.write( "10x + y - 54 = 10y + x
\n" ); document.write( "10x - x = 10y - y + 54
\n" ); document.write( "9x = 9y + 54
\n" ); document.write( "simplify, divide by 9
\n" ); document.write( "x = y + 6
\n" ); document.write( "Replace x with 3y
\n" ); document.write( "3y = y + 6
\n" ); document.write( "3y - y = 6
\n" ); document.write( "2y = 6
\n" ); document.write( "y = 3
\n" ); document.write( "then
\n" ); document.write( "x = 3(3)
\n" ); document.write( "x = 9
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\n" ); document.write( "93 is the number
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\n" ); document.write( "Check solution in the statement:
\n" ); document.write( "\"if 54 is subtracted from the number the digits are reversed.\"
\n" ); document.write( "93 - 54 = 39
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