document.write( "Question 511476: can someone help me with this one..\r
\n" ); document.write( "\n" ); document.write( "If the numerator and the denominator of a certain fraction are each decreased by 2, the value of the new fraction is 1/2. but if the numerator of the original fraction is increased by 1 and the denominator decreased by 2, the resulting fraction is equal to 3/4. Find the original fraction.\r
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Algebra.Com's Answer #342230 by oberobic(2304)\"\" \"About 
You can put this solution on YOUR website!
The original fraction is x/y.
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\n" ); document.write( "We're told:
\n" ); document.write( "x-2 / y -2 = 1/2
\n" ); document.write( "so
\n" ); document.write( "2(x-2) = y-2
\n" ); document.write( "2x -4 = y -2
\n" ); document.write( "2x -2 = y
\n" ); document.write( "so
\n" ); document.write( "y = 2x -2
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\n" ); document.write( "We're also told:
\n" ); document.write( "x+1 / y-2 = 3/4
\n" ); document.write( "so
\n" ); document.write( "4x+4 = 3y-6
\n" ); document.write( "3y = 4x + 10
\n" ); document.write( "y = 4/3x + 10/3
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\n" ); document.write( "Now we have two linear equations and two unknowns.
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\n" ); document.write( "We can graph them see where the intersect.
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\n" ); document.write( "\"graph%28500%2C500%2C-5%2C15%2C-5%2C15%2C2%2Ax-2%2C4%2F3%2Ax%2B10%2F3%29\"
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\n" ); document.write( "Or we can solve the two equations.
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\n" ); document.write( "y = 2x -2
\n" ); document.write( "3y = 4x + 10
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\n" ); document.write( "3y = 6x -6
\n" ); document.write( "3y = 4x +10
\n" ); document.write( "0 = 2x -16
\n" ); document.write( "2x = 16
\n" ); document.write( "x = 8
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\n" ); document.write( "substitute
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\n" ); document.write( "y = 2(8) -2
\n" ); document.write( "y = 14
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\n" ); document.write( "So it appears the first equation is
\n" ); document.write( "8/14
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\n" ); document.write( "But always check your answer
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\n" ); document.write( "(x-2)/(y-2) = 6/12 = 1/2
\n" ); document.write( "(x+1)/(y-2) = 9/12 = 3/4
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\n" ); document.write( "Answer: x=8, y=14
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\n" ); document.write( "Done.
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