document.write( "Question 511476: can someone help me with this one..\r
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document.write( "If the numerator and the denominator of a certain fraction are each decreased by 2, the value of the new fraction is 1/2. but if the numerator of the original fraction is increased by 1 and the denominator decreased by 2, the resulting fraction is equal to 3/4. Find the original fraction.\r
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document.write( "thank you! \n" );
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Algebra.Com's Answer #342230 by oberobic(2304)![]() ![]() ![]() You can put this solution on YOUR website! The original fraction is x/y. \n" ); document.write( ". \n" ); document.write( "We're told: \n" ); document.write( "x-2 / y -2 = 1/2 \n" ); document.write( "so \n" ); document.write( "2(x-2) = y-2 \n" ); document.write( "2x -4 = y -2 \n" ); document.write( "2x -2 = y \n" ); document.write( "so \n" ); document.write( "y = 2x -2 \n" ); document.write( ". \n" ); document.write( "We're also told: \n" ); document.write( "x+1 / y-2 = 3/4 \n" ); document.write( "so \n" ); document.write( "4x+4 = 3y-6 \n" ); document.write( "3y = 4x + 10 \n" ); document.write( "y = 4/3x + 10/3 \n" ); document.write( ". \n" ); document.write( "Now we have two linear equations and two unknowns. \n" ); document.write( ". \n" ); document.write( "We can graph them see where the intersect. \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "Or we can solve the two equations. \n" ); document.write( ". \n" ); document.write( "y = 2x -2 \n" ); document.write( "3y = 4x + 10 \n" ); document.write( ". \n" ); document.write( "3y = 6x -6 \n" ); document.write( "3y = 4x +10 \n" ); document.write( "0 = 2x -16 \n" ); document.write( "2x = 16 \n" ); document.write( "x = 8 \n" ); document.write( ". \n" ); document.write( "substitute \n" ); document.write( ". \n" ); document.write( "y = 2(8) -2 \n" ); document.write( "y = 14 \n" ); document.write( ". \n" ); document.write( "So it appears the first equation is \n" ); document.write( "8/14 \n" ); document.write( ". \n" ); document.write( "But always check your answer \n" ); document.write( ". \n" ); document.write( "(x-2)/(y-2) = 6/12 = 1/2 \n" ); document.write( "(x+1)/(y-2) = 9/12 = 3/4 \n" ); document.write( ". \n" ); document.write( "Answer: x=8, y=14 \n" ); document.write( ". \n" ); document.write( "Done. \n" ); document.write( " |