document.write( "Question 511467: A lab assistance want to make 5 liters 25.6% acid solution. if solutions of 40% and 16% are in stock, how many liters of each must be mixed to prepare the solution?
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Algebra.Com's Answer #342225 by oberobic(2304) $\"\"$ $\"About$

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You need 5 liters total. This needs to be 25.6% 'pure' acid.
\n" ); document.write( ".256*5 = 1.28 liters of pure acid in the 5 liters total solution.
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\n" ); document.write( "The amount of the 40% solution is: x
\n" ); document.write( "so, the amount of the 16% solution is: 5-x
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\n" ); document.write( ".40x + .16(5-x) = 1.28
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\n" ); document.write( "multiply by 100 to eliminate the decimal
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\n" ); document.write( "40x + 16(5-x) = 128
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\n" ); document.write( "40x + 80 -16x = 128
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\n" ); document.write( "24x = 48
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\n" ); document.write( "x = 2
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\n" ); document.write( "so
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\n" ); document.write( "5-x = 3
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\n" ); document.write( "Check to see if the amount of pure acid is correct.
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\n" ); document.write( ".4*2 + .16*3 = 1.28
\n" ); document.write( "which is exactly the amount of pure acid calculated at the start.
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\n" ); document.write( "Answer: Mix 2 liters of 40% acid and 3 liters of 16% acid to make 5 liters of 25.6% acid.
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\n" ); document.write( "Done. \n" ); document.write( "

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