document.write( "Question 511445: A plane flying with the wind went 350 miles in 2 hours. The return trip, flying against the wind, took 2.8 hours. Find the rate of the plane in calm air and the rate of the wind.
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Algebra.Com's Answer #342219 by oberobic(2304) ![]() You can put this solution on YOUR website! d = rt is the distance equation. \n" ); document.write( ". \n" ); document.write( "a = aircraft speed \n" ); document.write( "w = wind speed \n" ); document.write( ". \n" ); document.write( "Flying with the wind, the ground speed = a+w \n" ); document.write( ". \n" ); document.write( "(a+w) * 2 = 350 \n" ); document.write( "a + w = 175 \n" ); document.write( "a = 175-w \n" ); document.write( ". \n" ); document.write( "Flying against the wind, the ground speed = a-w \n" ); document.write( ". \n" ); document.write( "(a-w) * 2.8 = 350 \n" ); document.write( ". \n" ); document.write( "substitute a = (175-w) \n" ); document.write( ". \n" ); document.write( "(175-w -w) * 2.8 = 350 \n" ); document.write( ". \n" ); document.write( "175 -2w = 125 \n" ); document.write( ". \n" ); document.write( "-2w = -50 \n" ); document.write( ". \n" ); document.write( "w = 25 = wind speed \n" ); document.write( ". \n" ); document.write( "substitute \n" ); document.write( ". \n" ); document.write( "a + w = 175 \n" ); document.write( "a + 25 = 175 \n" ); document.write( "a = 150 = aircraft speed \n" ); document.write( ". \n" ); document.write( "Check the answer. \n" ); document.write( ". \n" ); document.write( "(150-25)*x = 350 \n" ); document.write( "125x = 350 \n" ); document.write( "x = 2.8 \n" ); document.write( "Correct. \n" ); document.write( ". \n" ); document.write( "Answer: The aircraft flies 150 mph and the wind is 25 mph. \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( " |