document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=511397>Question 511397</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 1.	Suppose we want to determine the (binomial) probability (p) of getting 6 heads in 13 flips of a 2-sided coin.  Using Table 2 in Appendix B of the text, what values of n, x, and p would we use to look up this probability, and what would be the probability?\r<BR>\n" );
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document.write( "This is what I think I know:\r<BR>\n" );
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document.write( "n = 11<BR>\n" );
document.write( "x = 6<BR>\n" );
document.write( "p = .50q = 1-p = .50\r<BR>\n" );
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document.write( "I think this is the forumula I use:\r<BR>\n" );
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document.write( "11/(11-6)6 (.50)^2(.50)^5 =\r<BR>\n" );
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document.write( "I can't figure out any more or even if what I have done is correct.  I need some line for line, number to number detail so I can really learn and understand this please. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #342195 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=342195\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  Suppose we want to determine the (binomial) probability (p) of getting 6 heads in 13 flips of a 2-sided coin.<BR>\n" );
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document.write( "The 6 heads can show up is 13C6 = 1716 mutually exclusive ways.<BR>\n" );
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document.write( "Each of those ways has probability (1/2)^6*(1/2)^7 = 1/2^13 = 1/8192 <BR>\n" );
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document.write( "Because the 1716 ways to succeed are mutually exclusive you should<BR>\n" );
document.write( "add all 1716 of those separate probabilities to get the final probability.<BR>\n" );
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document.write( "You could add but it's easier to just multiply 1716*(1/8192) = 0.2095<BR>\n" );
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document.write( "In general, if there are n trials, and the probability of success<BR>\n" );
document.write( "on each trial is \"p\", the probability of \"k\" successes is as follows:<BR>\n" );
document.write( "P(x = k) = nCk*p^k*q^(n-k)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "stan H.<BR>\n" );
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