document.write( "Question 511293: Pleasee help me solve this equation:
\n" ); document.write( "Find the slope-intercept form of the equation of the line that passes through the point (6,5) and is parallel to the line 4x-3y=4.
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Algebra.Com's Answer #342194 by mananth(16946)\"\" \"About 
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4 x + -3 y = 4
\n" ); document.write( "Find the slope of this line
\n" ); document.write( "make y the subject
\n" ); document.write( "-3 y = -4 x + 4
\n" ); document.write( "Divide by -3
\n" ); document.write( " y = 1.33 x -1.33
\n" ); document.write( "Compare this equation with y=mx+b
\n" ); document.write( "slope m = 1.33 0.8
\n" ); document.write( "The slope of a line parallel to the above line will be the same
\n" ); document.write( "The slope of the required line will be 4/3
\n" ); document.write( "m= 4/3 ,point ( 6 , 5 )
\n" ); document.write( "Find b by plugging the values of m & the point in
\n" ); document.write( "y=mx+b
\n" ); document.write( "5 = 8.00 + b
\n" ); document.write( "b= -3
\n" ); document.write( "m= 4/3
\n" ); document.write( "Plug value of the slope and b in y = mx +b
\n" ); document.write( "The required equation is y = 4/3 x -3
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\n" ); document.write( "m.ananth@hotmail.ca
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