document.write( "Question 511300: Please help me solve this equation:
\n" ); document.write( "What is the standard form of the equation of the line that is perpendicular to 6x+5y=0 and contains (-6,-1)? \n" ); document.write( "

Algebra.Com's Answer #342193 by mananth(16946) $\"\"$ $\"About$

You can put this solution on YOUR website!
6 x + 5 y = 0
\n" ); document.write( "Find the slope of this line
\n" ); document.write( "
\n" ); document.write( "5 y = -6 x + 0
\n" ); document.write( "Divide by 5
\n" ); document.write( " y = -1.200 x + 0
\n" ); document.write( "Compare this equation with y=mx+b
\n" ); document.write( "slope m = -1.20
\n" ); document.write( "
\n" ); document.write( "The slope of a line perpendicular to the above line will be the negative reciprocal 0.83
\n" ); document.write( "m1*m2=-1
\n" ); document.write( "The slope of the required line will be 5/6
\n" ); document.write( "
\n" ); document.write( "m= 5/6 ,point ( -6 , -1 )
\n" ); document.write( "Find b by plugging the values of m & the point in
\n" ); document.write( "y=mx+b
\n" ); document.write( "-1 = -5.00 + b
\n" ); document.write( "b= 4
\n" ); document.write( "m= 5/6
\n" ); document.write( "The required equation is y = 5/ 6 x + 4
\n" ); document.write( "m.ananth@hotmail.ca
\n" ); document.write( " \n" ); document.write( "

\n" );