document.write( "Question 511374: hi can someone help me with this..\r
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document.write( "A man can row 12 miles upstream in a river and back in 7 1/2 hours. He can row 1 mile upstream in th same time that he can row 4 miles downstream. Find the speed of the boat in still water and the speed of the current. \n" );
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Algebra.Com's Answer #342184 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! A man can row 12 miles upstream in a river and back in 7 1/2 hours. He can row 1 mile upstream in th same time that he can row 4 miles downstream. Find the speed of the boat in still water and the speed of the current. \n" ); document.write( "** \n" ); document.write( "2 conditions given, so use 2 equations to solve:\r \n" ); document.write( "\n" ); document.write( "let x=speed of boat in still water \n" ); document.write( "let c=speed of current \n" ); document.write( "x+c =speed of boat downstream \n" ); document.write( "x-c = speed of boat upstream \n" ); document.write( ".. \n" ); document.write( "Travel time=distance/speed \n" ); document.write( "1/(x-c)=4/(x+c) \n" ); document.write( "x+c=4x-4c \n" ); document.write( "5c=3x \n" ); document.write( "c=3x/5 \n" ); document.write( ".. \n" ); document.write( "12/(x-c)+12/(x+c)=7.5 \n" ); document.write( "LCD:(x+c)(x-c) \n" ); document.write( "12x+12c+12x-12c=7.5(x+c)(x-c) \n" ); document.write( "24x=7.5(x^2-c^2) (difference of squares) \n" ); document.write( "24x=7.5(x^2-(3x/5)^2)=7.5(x^2-9x^2/25)=7.5[(25x^2-9x^2)/25] \n" ); document.write( "24x=7.5[16x^2/25]=(7.5/25)(16x^2)=.3(16x^2)=4.8x^2 \n" ); document.write( "4.8x^2-24x=0 \n" ); document.write( "x(4.8x-24=0 \n" ); document.write( "x=0 (reject, speed>0) \n" ); document.write( "4.8x-24=0 \n" ); document.write( "x=24/4.8=5 mph \n" ); document.write( "c=3x/5=15/5=3mph \n" ); document.write( "ans: \n" ); document.write( "speed of boat in still water=5 mph \n" ); document.write( "speed of current=3 mph \n" ); document.write( " |