document.write( "Question 511377: A man is 4 years older than his wife and 5 times as old as his son. When the son was born, the age of the wife was six-sevenths that of her husband's age. Find the age of each. \n" ); document.write( "
Algebra.Com's Answer #342181 by lwsshak3(11628)\"\" \"About 
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A man is 4 years older than his wife and 5 times as old as his son. When the son was born, the age of the wife was six-sevenths that of her husband's age. Find the age of each.
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\n" ); document.write( "let x=wife's age
\n" ); document.write( "x+4=husband's age
\n" ); document.write( "(x+4)/5=son's age
\n" ); document.write( "..
\n" ); document.write( "x/(x+4)=6/7
\n" ); document.write( "7x=6x+24
\n" ); document.write( "x=24
\n" ); document.write( "x+4=28
\n" ); document.write( "(x+4)/5=28/5=5.6
\n" ); document.write( "ans:
\n" ); document.write( "wife's age=24
\n" ); document.write( "husband's age=28
\n" ); document.write( "son's age=5.6
\n" ); document.write( "
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