document.write( "Question 511377: A man is 4 years older than his wife and 5 times as old as his son. When the son was born, the age of the wife was six-sevenths that of her husband's age. Find the age of each. \n" ); document.write( "
Algebra.Com's Answer #342180 by mananth(16946)\"\" \"About 
You can put this solution on YOUR website!
Let wife's age be x \r
\n" ); document.write( "\n" ); document.write( "man's age = x+4\r
\n" ); document.write( "\n" ); document.write( "son's age = 1/5 * (x+4)\r
\n" ); document.write( "\n" ); document.write( "wife'a age when son was born : ( x- 1/5(x+4))\r
\n" ); document.write( "\n" ); document.write( "Husband's age when son was born ((x+4)-(1/5*(x+4))\r
\n" ); document.write( "\n" ); document.write( "6/7((x+4)-(1/5*(x+4))=( x- 1/5(x+4))\r
\n" ); document.write( "\n" ); document.write( "6/7(x+4 -((x+4)/5)) = (x-((x+4)/5))
\n" ); document.write( "LCD = 5 \r
\n" ); document.write( "\n" ); document.write( "6/7(5x+20-x-4)/5 = (5x-x-4)/5\r
\n" ); document.write( "\n" ); document.write( "6/7(4x+16)/5 = 4x-4)/5\r
\n" ); document.write( "\n" ); document.write( "6/7(4x+16) = 4x-4\r
\n" ); document.write( "\n" ); document.write( "6(4x+16) = 7(4x-4)\r
\n" ); document.write( "\n" ); document.write( "24x+96=28x-28
\n" ); document.write( "4x=96+28
\n" ); document.write( "4x=124
\n" ); document.write( "x=31 Age of wife years\r
\n" ); document.write( "\n" ); document.write( "Age of Man = 31+4 = 35 years\r
\n" ); document.write( "\n" ); document.write( "Age of son = 1/5*35 =7 years.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "
\n" );