document.write( "Question 51265: A rectangular garden is to be surrounded by a walkway of constant width. The garden's dimensions are 30 ft by 40 ft. The total area, garden plus walkway, is to be 1800 ft^2. What must be the width of the walkway to the nearest thousandth? \n" ); document.write( "
Algebra.Com's Answer #34218 by checkley71(8403)![]() ![]() ![]() You can put this solution on YOUR website! (30+2X)(40+2X)=1800 OR 1200+80X+60X+4X^2=1800 OR 4X^2+140X-600=0 OR \r \n" ); document.write( "\n" ); document.write( "X^2+35X-150=0 OR x=3.86 ft wide walkway (using the quadratic equation)\r \n" ); document.write( "\n" ); document.write( "proof (30+2*3.86)(40+2*3.86)=1800 or (30+7.72)(40+7.72)=1800 or \r \n" ); document.write( "\n" ); document.write( "37.72*47.72=1800 or 1800=1800 \n" ); document.write( " |