document.write( "Question 511334: How many gallons of water must be added to 40 gallons of 10% alcohol solution to produce an 8% alcohol solution? \n" ); document.write( "
Algebra.Com's Answer #342164 by Maths68(1474)\"\" \"About 
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Water
\n" ); document.write( "Amount = x
\n" ); document.write( "Concentration = 0% =0 (Water is pure therefore alcohal concentration will be 0%)
\n" ); document.write( "================================================================================
\n" ); document.write( "Alcohol
\n" ); document.write( "Amount =40
\n" ); document.write( "Concentration =10% = 0.10
\n" ); document.write( "================================================================================
\n" ); document.write( "Mixture
\n" ); document.write( "Amount = (40+x) gallons
\n" ); document.write( "Concentration = 8%=0.08
\n" ); document.write( "===============================================================================
\n" ); document.write( "[Water Amount *Concentration of Water] + [Alcohol Amount *Alcohol Concentration ] = Amount of Mixture * Concentration of Mixture
\n" ); document.write( "(x*0)+(40)*(0.10)=(0.08)*(40+x)
\n" ); document.write( "0+4=3.2+0.08x
\n" ); document.write( "4-3.2=0.08x
\n" ); document.write( "0.8=0.08x
\n" ); document.write( "0.8/0.08=0.08x/0.08
\n" ); document.write( "10=x
\n" ); document.write( "x=10
\n" ); document.write( "===============================================================================
\n" ); document.write( "Water
\n" ); document.write( "Amount = x =10 gallons
\n" ); document.write( "Concentration = 0% =0\r
\n" ); document.write( "\n" ); document.write( "Alcohol
\n" ); document.write( "Amount =40 gallons
\n" ); document.write( "Concentration =10% = 0.10\r
\n" ); document.write( "\n" ); document.write( "Mixture
\n" ); document.write( "Amount = (40+x) = (40+10) = 50 gallons
\n" ); document.write( "Concentration = 8%=0.08
\n" ); document.write( "===============================================================================
\n" ); document.write( "10 gallons of water must be added to 40 gallons of 10% alcohol solution to produce a 50 gallons of 8% alcohol solution.
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