document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=511345>Question 511345</A>: <I><SPAN STYLE=\"word-break: break-all;\"> For all integers p and q, let # be defined by p # q = p^2 + q^2 + 2pq .  Which of the following CANNOT be the value of p # q?\r<BR>\n" );
document.write( "\n" );
document.write( "a.1<BR>\n" );
document.write( "b.0<BR>\n" );
document.write( "c.9<BR>\n" );
document.write( "d.4<BR>\n" );
document.write( "e.2 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #342158 by </B><A HREF=/tutors/aboutme.mpl?userid=richard1234><B>richard1234(7193)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richard1234><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richard1234><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=342158\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> It is apparent that p # q = (p+q)^2. Since the function is only defined on integers p and q, the domain must be the perfect squares, so E)2 cannot be the value of p # q. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );