document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=511313>Question 511313</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the depreciation for the corporate airplane from 2006<BR>\n" );
document.write( "to 2009. The plane was purchased new in 2006; therefore, x = 0 represents the year 2006.\r<BR>\n" );
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document.write( "X &#65533; axis (horizontal) = years starting from 0 = 2006 and increasing by 0.5 years\r<BR>\n" );
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document.write( "Y &#65533; axis (vertical) = price in $ amounts from 24,000 to 240,000\r<BR>\n" );
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document.write( "List the coordinates of two points on the graph in (x, y) form. \r<BR>\n" );
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document.write( "(2.0, 216000),(3.0,204000)\r<BR>\n" );
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document.write( "b) Find the slope (rate of depreciation) of this line:\r<BR>\n" );
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document.write( "c) Find the linear equation of this line in slope-intercept form.\r<BR>\n" );
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document.write( "d) If the rate of depreciation continues at the present rate, what will be the plane’s<BR>\n" );
document.write( "value in the year 2017? Show how to use the linear equation from part c) to<BR>\n" );
document.write( "obtain your answer.\r<BR>\n" );
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document.write( "e) If the trend continued, in how many years would the plane’s value be $48000?<BR>\n" );
document.write( "Show how to use the linear equation from part c) to obtain your answer.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #342149 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=342149\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the depreciation for the corporate airplane from 2006<BR>\n" );
document.write( "to 2009. The plane was purchased new in 2006; therefore, x = 0 represents the year 2006.\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "X &#65533; axis (horizontal) = years starting from 0 = 2006 and increasing by 0.5 years\r<BR>\n" );
document.write( "\n" );
document.write( "Y &#65533; axis (vertical) = price in $ amounts from 24,000 to 240,000\r<BR>\n" );
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document.write( "List the coordinates of two points on the graph in (x, y) form. <BR>\n" );
document.write( "(2.0, 216000),(3.0,204000)<BR>\n" );
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document.write( "b) Find the slope (rate of depreciation) of this line:<BR>\n" );
document.write( "slope = (204000-216000)/(3-2) = -12000\r<BR>\n" );
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document.write( "c) Find the linear equation of this line in slope-intercept form.<BR>\n" );
document.write( "Form: y = mx+b<BR>\n" );
document.write( "216000 = -12000*2 + b<BR>\n" );
document.write( "b = 240000<BR>\n" );
document.write( "y = -12000x + 240000<BR>\n" );
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document.write( "d) If the rate of depreciation continues at the present rate, what will be the plane’s value in the year 2017? Show how to use the linear equation from part c) to obtain your answer.<BR>\n" );
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document.write( "2017-2006 = 11<BR>\n" );
document.write( "f(11) = -12000*11+240000 = $108,000<BR>\n" );
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document.write( "e) If the trend continued, in how many years would the plane’s value be $48000?<BR>\n" );
document.write( "Show how to use the linear equation from part c) to obtain your answer.<BR>\n" );
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document.write( "Solve: -12000x + 240,000 = 48000<BR>\n" );
document.write( "-12000x = -192000<BR>\n" );
document.write( "x = 16 years<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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document.write( " </SPAN>\n" );
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