document.write( "Question 51260: State the domain and range of f^-1 (x), given
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document.write( "f(x)=(x-1)^2 +2 ** Please note their should be brackets around x-1 part** I'm not sure if the brackets will show up for you.\r
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document.write( "This is what I have tried so far. I tried to find the inverse I am not sure if i am right.\r
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document.write( "f(x)= (x-1)^2+2
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document.write( "y=(x-1)^2+2
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document.write( "(y-1)^2=x-2
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document.write( "y-1= +/- Square root x-2
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document.write( "y= +/- square root x-2+1
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document.write( "f^-1 (x) = +/- square root x-2+1
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document.write( "Now I think I have to find the domain and range of this f^-1 (x) = +/- square root x-2+1. I am not sure how to do this. Can you please check my work and see if it is ok so far and help me find the domain and range and if I have made a mistake can you help me correct it. Thank-you so much.
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Algebra.Com's Answer #34208 by Nate(3500)![]() ![]() ![]() You can put this solution on YOUR website! f(x) = (x - 1)^2 + 2 \n" ); document.write( "y = (x - 1)^2 + 2 \n" ); document.write( "x = (y - 1)^2 + 2 \n" ); document.write( "x - 2 = (y - 1)^2 \n" ); document.write( "+- \n" ); document.write( "+- \n" ); document.write( "Domain: {x| \n" ); document.write( "Range: {y|all reals} \n" ); document.write( " |