document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=51259>Question 51259</A>: <I><SPAN STYLE=\"word-break: break-all;\"> State the domain and range of f^-1 (x) given <BR>\n" );
document.write( "a) f(x)= x+3 <BR>\n" );
document.write( "This is what I have tried so far:) I found the inverse of the question I think this is right.<BR>\n" );
document.write( "y=x+3<BR>\n" );
document.write( "x=y+3<BR>\n" );
document.write( "x-y=3<BR>\n" );
document.write( "-y=3-x<BR>\n" );
document.write( "y=x-3<BR>\n" );
document.write( "f^-1(x) = x-3 now I know I have to find the domain and range of f^1(x) =x-3 but I am extremely confused on how to do this I know x value is domain and y is range. Can you please help me find the correct answer. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #34206 by </B><A HREF=/tutors/aboutme.mpl?userid=Nate><B>Nate(3500)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Nate><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=34206\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> There are no limitations to f^-1(x) = x - 3 , so the answer for the domain is all real values. </SPAN>\n" );
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