document.write( "Question 511152: Find an equation of a line through (-2,-2) and parallel to \r
\n" ); document.write( "\n" ); document.write( "Line A: y - 2x + 5 = 0 \r
\n" ); document.write( "\n" ); document.write( "Show all work and give the equation in Slope-Intercept form.
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Algebra.Com's Answer #342024 by Maths68(1474)\"\" \"About 
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Given line
\n" ); document.write( "y - 2x + 5 = 0 and point (-2,-2)
\n" ); document.write( "Rearrange the equation
\n" ); document.write( "y - 2x + 5 = 0
\n" ); document.write( "y=2x-5
\n" ); document.write( "Slope of the given line = 2
\n" ); document.write( "Since lines are parallel their slopes will be same
\n" ); document.write( "slope of the required will be = 2
\n" ); document.write( "Now we have a point and slope we can put the values in point-slope form of the equation to find the required line
\n" ); document.write( "y2-y1/x2-x1=m
\n" ); document.write( "-2-y/-2-x=2
\n" ); document.write( "-2-y=(-2-x)2
\n" ); document.write( "-2-y=-4-2x
\n" ); document.write( "-(2+y)=-(4+2x)
\n" ); document.write( "2+y=4+2x
\n" ); document.write( "y=4+2x-2
\n" ); document.write( "y=2x-2
\n" ); document.write( "Above equation is the required equation of the line in slope-intercept form (y=mx+b)
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