document.write( "Question 511104: I hope you can help me :)
\n" ); document.write( "problem is..\r
\n" ); document.write( "\n" ); document.write( "Find (a) tan(x+y) (b) tan(x-y) through tan x = 7/3,0\n" ); document.write( "\n" ); document.write( "Thanks!
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Algebra.Com's Answer #341999 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
Find
\n" ); document.write( "(a) tan(x+y)
\n" ); document.write( "= [tan(x)+tan(y)]/[1-tan(x)*tan(y)]
\n" ); document.write( "---
\n" ); document.write( "= [7/3 + 3/4]/[1 - (7/3)(3/4)]
\n" ); document.write( "---
\n" ); document.write( "= [37/12] / [1 - (7/4)]
\n" ); document.write( "---
\n" ); document.write( "= (37/12)/(-3/4)
\n" ); document.write( "--
\n" ); document.write( "= (37/12)*(-4/3)
\n" ); document.write( "= -36/9
\n" ); document.write( "=========================
\n" ); document.write( "(b) tan(x-y)
\n" ); document.write( "= [tan(x)-tan(y)]/[1+tan(x)*tan(y)]
\n" ); document.write( "---
\n" ); document.write( "= [7/3 - 3/4]/[1 + (7/3)(3/4)]
\n" ); document.write( "---
\n" ); document.write( "= [18/12] / [1 + (7/4)]
\n" ); document.write( "---
\n" ); document.write( "= (3/2)/(11/4)
\n" ); document.write( "--
\n" ); document.write( "= (3/2)*(4/11)
\n" ); document.write( "----
\n" ); document.write( "= 6/11
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\n" ); document.write( "---\r
\n" ); document.write( "\n" ); document.write( "tan x = 7/3, 0\n" ); document.write( "===============
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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