document.write( "Question 511104: I hope you can help me :)
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document.write( "problem is..\r
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document.write( "Find (a) tan(x+y) (b) tan(x-y) through tan x = 7/3,0
Algebra.Com's Answer #341999 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! Find \n" ); document.write( "(a) tan(x+y) \n" ); document.write( "= [tan(x)+tan(y)]/[1-tan(x)*tan(y)] \n" ); document.write( "--- \n" ); document.write( "= [7/3 + 3/4]/[1 - (7/3)(3/4)] \n" ); document.write( "--- \n" ); document.write( "= [37/12] / [1 - (7/4)] \n" ); document.write( "--- \n" ); document.write( "= (37/12)/(-3/4) \n" ); document.write( "-- \n" ); document.write( "= (37/12)*(-4/3) \n" ); document.write( "= -36/9 \n" ); document.write( "========================= \n" ); document.write( "(b) tan(x-y) \n" ); document.write( "= [tan(x)-tan(y)]/[1+tan(x)*tan(y)] \n" ); document.write( "--- \n" ); document.write( "= [7/3 - 3/4]/[1 + (7/3)(3/4)] \n" ); document.write( "--- \n" ); document.write( "= [18/12] / [1 + (7/4)] \n" ); document.write( "--- \n" ); document.write( "= (3/2)/(11/4) \n" ); document.write( "-- \n" ); document.write( "= (3/2)*(4/11) \n" ); document.write( "---- \n" ); document.write( "= 6/11 \n" ); document.write( " \n" ); document.write( "---\r \n" ); document.write( "\n" ); document.write( "tan x = 7/3, 0 \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |