document.write( "Question 510965: A radiator contains 14 quarts of fluid, 25% of which is antifreeze. How much fluid should be drained and replaced with pure antifreeze so that the new mixture is 50% antifreeze? (Round your answer to two decimal places.)
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Algebra.Com's Answer #341958 by mananth(16946)\"\" \"About 
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---------percent ---------------- quantity
\n" ); document.write( "Antifreeze 100 ---------------- x quarts
\n" ); document.write( "Fluid 25---------------- 14 - x quarts
\n" ); document.write( "Mixture 50 ---------------- 14
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\n" ); document.write( "100 x + 25 ( 14 - x ) = 50 * 14
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\n" ); document.write( "100 x + 350 - 25 x = 700
\n" ); document.write( "100 x - 25 x = 700 - 350
\n" ); document.write( "75 x = 350
\n" ); document.write( "/ 75
\n" ); document.write( " x=4.67 quarts 100.00% Antifreeze
\n" ); document.write( " 9.33 quarts 25.00% Fluid
\n" ); document.write( "4.67 quarts has to be drained
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