document.write( "Question 510962: The father is 35 the son is 9. How many years will it take the son to be 3 times his fathers age. I have two different answers that I do not know if they are correct. I have tried 35-9= 26X3 = 78. I have also tried 35x3= 105/9 =11.667. \n" ); document.write( "
Algebra.Com's Answer #341953 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! The father is 35 the son is 9. How many years will it take the son to be 3 times his fathers age. \n" ); document.write( "--------- \n" ); document.write( "Note: The son will never be older than the father.\r \n" ); document.write( "\n" ); document.write( "Equation: \n" ); document.write( "Let the number of years be \"x\". \n" ); document.write( "(9+x) = 3(35+x) \n" ); document.write( "9+x = 115 = 3x \n" ); document.write( "2x = - 106 \n" ); document.write( "--- \n" ); document.write( "x = -53 \n" ); document.write( "---- \n" ); document.write( "Father's age: 35-53 = -18 \n" ); document.write( "Son's age: 9-53 = -44 \n" ); document.write( "Nonsense \n" ); document.write( "======================= \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "=============== \n" ); document.write( " |