document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=510962>Question 510962</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The father is 35 the son is 9.  How many years will it take the son to be 3 times his fathers age.  I have two different answers that I do not know if they are correct.  I have tried 35-9= 26X3 = 78.   I have also tried 35x3= 105/9 =11.667. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #341952 by </B><A HREF=/tutors/aboutme.mpl?userid=oberobic><B>oberobic(2304)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=oberobic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=341952\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 35+x = 3(9+x)<BR>\n" );
document.write( "35+x = 27 + 3x<BR>\n" );
document.write( "-2x = -8<BR>\n" );
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document.write( "x = 4<BR>\n" );
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document.write( "In 4 years, the father will be 39 and the son will be 13.  39 = 3*13.<BR>\n" );
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document.write( "It is impossible for a son to be 3 times the father's age ever, so I solved it the other way.<BR>\n" );
document.write( "The father will be 3 times the son's age in 4 years.<BR>\n" );
document.write( ".<BR>\n" );
document.write( "Done. </SPAN>\n" );
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