document.write( "Question 510937: Matthew is 3 times as old as Jenny. In 7 years he will be twice as old as she will be then. How old is each now.
\n" ); document.write( "I have figured out the answer, but not how to work the problem. I tried:
\n" ); document.write( "x + 1/3X = 2 times X + 7 + 1/3 X + 7 which is completely wrong. I have not done a problen where I didn't have a specific number for an answer. Reid \n" ); document.write( "
Algebra.Com's Answer #341941 by oberobic(2304)\"\" \"About 
You can put this solution on YOUR website!
M = 3*J
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\n" ); document.write( "In 7 years, their ages will be:
\n" ); document.write( "M+7
\n" ); document.write( "J+7
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\n" ); document.write( "M+7 = 2*(J+7)
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\n" ); document.write( "Substitute M=3*J
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\n" ); document.write( "3J + 7 = 2J + 14
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\n" ); document.write( "J = 7
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\n" ); document.write( "M = 3J = 21
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\n" ); document.write( "Check their age relationship in 7 years.
\n" ); document.write( "M+7 = 28
\n" ); document.write( "J+7= 14
\n" ); document.write( "M+7 = 2(J+7)
\n" ); document.write( "Correct.
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\n" ); document.write( "Answer: Matthew is 21, and Jenny is 7.
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\n" ); document.write( "Done. \n" ); document.write( "
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