document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=510937>Question 510937</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Matthew is 3 times as old as Jenny. In 7 years he will be twice as old as she will be then. How old is each now.<BR>\n" );
document.write( "I have figured out the answer, but not how to work the problem. I tried:<BR>\n" );
document.write( "x + 1/3X = 2 times X + 7 + 1/3 X + 7 which is completely wrong. I have not done a problen where I didn't have a specific number for an answer. Reid  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #341940 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=341940\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Matthew is 3 times as old as Jenny.<BR>\n" );
document.write( "m = 3j<BR>\n" );
document.write( " In 7 years he will be twice as old as she will be then.<BR>\n" );
document.write( "m + 7 = 2(j+7)<BR>\n" );
document.write( "m + 7 = 2j + 14<BR>\n" );
document.write( "m = 2j + 14 - 7<BR>\n" );
document.write( "m = 2j + 7<BR>\n" );
document.write( "Replace m with 3j<BR>\n" );
document.write( "3j = 2j + 7<BR>\n" );
document.write( "3j - 2j = 7<BR>\n" );
document.write( "j = 7 yrs<BR>\n" );
document.write( "then obviously<BR>\n" );
document.write( "m = 21 yrs\r<BR>\n" );
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document.write( " </SPAN>\n" );
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