document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=510925>Question 510925</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the domain of (f/g)(x) when f(x)=2x^2-5x and g(x)=x^2-2x-7 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #341929 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=341929\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Find the domain of (f/g)(x) when f(x)=2x^2-5x and g(x)=x^2-2x-7<BR>\n" );
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document.write( "(f/g)(x) = (2x^2-5x)/(x^2-2x-7)<BR>\n" );
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document.write( "Factor:<BR>\n" );
document.write( "= (x(2x-5))/(x^2-2x-7)<BR>\n" );
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document.write( "Since b^2 - 4ac = 2^2-4*1*-7 = 4+28 >0<BR>\n" );
document.write( "x = [2 +- sqrt(4+28)]/2<BR>\n" );
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document.write( "x = [2 +- sqrt(32)]/2<BR>\n" );
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document.write( "x = [2 +- 4sqrt(2)]/2<BR>\n" );
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document.write( "x = 1 + 2sqrt(2) or x = 1-2sqrt(2)<BR>\n" );
document.write( "--<BR>\n" );
document.write( "These Real numbers are missing from the domain which is otherwise<BR>\n" );
document.write( "All Real Numbers.<BR>\n" );
document.write( "======================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "====================== </SPAN>\n" );
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