document.write( "Question 510705: It took 2 hours for 1 person to sweep the yard. How long would it take 4 persons working at the same speed to do the same job?\r
\n" ); document.write( "\n" ); document.write( "My attempt:
\n" ); document.write( "Firstly, it has to take less than 2 hours since the number of persons has been increased.\r
\n" ); document.write( "\n" ); document.write( "The # of persons has been increased by 3 so: \r
\n" ); document.write( "\n" ); document.write( "Increase in persons/ Time = 3 / 2 \r
\n" ); document.write( "\n" ); document.write( "1.5 hours.\r
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Algebra.Com's Answer #341925 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
It took 2 hours for 1 person to sweep the yard.
\n" ); document.write( " How long would it take 4 persons working at the same speed to do the same job?
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\n" ); document.write( "Assume they each had broom, and worked at the same rate (2hrs to complete the job)
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\n" ); document.write( "Let t = time required by 4 men doing the job
\n" ); document.write( "Let the completed job = 1
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\n" ); document.write( "Each will do a fraction of the job, and the fractions will add up to 1
\n" ); document.write( "\"t%2F2\" + \"t%2F2\" + \"t%2F2\" + \"t%2F2\" = 1
\n" ); document.write( "Multiply thru by 2
\n" ); document.write( "t + t + t + t = 2
\n" ); document.write( "4t = 2
\n" ); document.write( "t = \"2%2F4\"
\n" ); document.write( "t = \"1%2F2\" hr with all 4 men sweeping
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