document.write( "Question 510903: A woman invested 4 times as much at 2% as she did at 6%. The total amount of interest she earns in 1 year from both accounts is $560. How much did she invest at each rate?\r
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Algebra.Com's Answer #341920 by stanbon(75887)\"\" \"About 
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A woman invested 4 times as much at 2% as she did at 6%. The total amount of interest she earns in 1 year from both accounts is $560. How much did she invest at each rate? \r
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\n" ); document.write( "Equations:
\n" ); document.write( "Quantity: x - 4y = 0
\n" ); document.write( "Interest:0.06x + 0.02y = 560
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\n" ); document.write( "Multiply Quantity by 6
\n" ); document.write( "Multiply Interest by 100
\n" ); document.write( "6x - 24y = 0
\n" ); document.write( "6x + 2y = 56000
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\n" ); document.write( "Subtract and solve for \"y\":
\n" ); document.write( "26y = 56000
\n" ); document.write( "y = $2153.85
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\n" ); document.write( "Solve for \"x\":
\n" ); document.write( "x = $8115.39
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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