document.write( "Question 510670: if you had 80 coins some of them are 1 dollar coins and the rest were 50 cent coins the total amount added up to 50 dollars how many coins of each kind were there? \n" ); document.write( "
Algebra.Com's Answer #341847 by ptaylor(2198)\"\" \"About 
You can put this solution on YOUR website!
Let x=number of 1 dollar coins
\n" ); document.write( "And y=number of 50 cent=1/2 dollar coins
\n" ); document.write( "so:
\n" ); document.write( "x*1+y*(1/2)=50 ---$ understood or
\n" ); document.write( "x+(1/2)y=50-----------------------------------eq1
\n" ); document.write( "and
\n" ); document.write( "x+y=80-----------------------------------------eq2
\n" ); document.write( "subtract eq1 from eq2
\n" ); document.write( "(1/2)y=30
\n" ); document.write( "y=60---------------------------number of 1/2 dollars
\n" ); document.write( "x=80-y=80-60=20-------------- number of dollars
\n" ); document.write( "CK
\n" ); document.write( "60*(1/2)+20*1=50
\n" ); document.write( "50=50\r
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\n" ); document.write( "\n" ); document.write( "Hope this helps----ptaylor
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