document.write( "Question 510670: if you had 80 coins some of them are 1 dollar coins and the rest were 50 cent coins the total amount added up to 50 dollars how many coins of each kind were there? \n" ); document.write( "
Algebra.Com's Answer #341847 by ptaylor(2198)![]() ![]() You can put this solution on YOUR website! Let x=number of 1 dollar coins \n" ); document.write( "And y=number of 50 cent=1/2 dollar coins \n" ); document.write( "so: \n" ); document.write( "x*1+y*(1/2)=50 ---$ understood or \n" ); document.write( "x+(1/2)y=50-----------------------------------eq1 \n" ); document.write( "and \n" ); document.write( "x+y=80-----------------------------------------eq2 \n" ); document.write( "subtract eq1 from eq2 \n" ); document.write( "(1/2)y=30 \n" ); document.write( "y=60---------------------------number of 1/2 dollars \n" ); document.write( "x=80-y=80-60=20-------------- number of dollars \n" ); document.write( "CK \n" ); document.write( "60*(1/2)+20*1=50 \n" ); document.write( "50=50\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Hope this helps----ptaylor \n" ); document.write( " \n" ); document.write( " |