document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=510652>Question 510652</A>: <I><SPAN STYLE=\"word-break: break-all;\"> in a chemistry class 7 liters of a 4% SILVER IODIDE SOLUTION MUST BE MIXED WITH A 10% SOLUTION TO GET A 6% SOLUTION. HOW MANY LITERS OF THE 10% SOLUTION ARE NEEDED? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #341846 by </B><A HREF=/tutors/aboutme.mpl?userid=ptaylor><B>ptaylor(2198)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ptaylor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ptaylor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=341846\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x=number of liters of 10% solution needed<BR>\n" );
document.write( "Now we know that the pure silver iodide that exists before the mixture takes place has to equal the amount that exists after the mixture takes place, so:<BR>\n" );
document.write( "0.04*7+0.10x=0.06(7+x)<BR>\n" );
document.write( "0.28+0.10x=0.42+0.06x  subtract 0.28 and also 0.06x from each side<BR>\n" );
document.write( "0.28-0.28+0.10x-0.06x=0.42-0.28+0.06x-0.06x  collect like terms<BR>\n" );
document.write( "0.04x=0.14<BR>\n" );
document.write( "x=3.5 liters------amount of 10% solution needed\r<BR>\n" );
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document.write( "CK<BR>\n" );
document.write( "0.04*7+0.10*3.5=0.06*10.5<BR>\n" );
document.write( "0.28+0.35=0.63<BR>\n" );
document.write( "0.63=0.63\r<BR>\n" );
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document.write( "Hope this helps---ptaylor\r<BR>\n" );
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document.write( " </SPAN>\n" );
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