document.write( "Question 510573: Determine the probability that in a class of 8 students, at least two students have the same birthday. Assume that there are always 365 days in a year and that birth rates are constant throughout the year. (Hint: First determine the probability that no two students have the same birthday and then apply the complementation rule.)\r
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document.write( "Please help! Thanks, Sue \n" );
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Algebra.Com's Answer #341840 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! Determine the probability that in a class of 8 students, at least two students have the same birthday. Assume that there are always 365 days in a year and that birth rates are constant throughout the year. (Hint: First determine the probability that no two students have the same birthday and then apply the complementation rule.) \r \n" ); document.write( "\n" ); document.write( "---- \n" ); document.write( "1st: 1 \n" ); document.write( "2nd: (1-(1/365)) = (364/365 \n" ); document.write( "3rd: (1-(2/365)) = (363/365 \n" ); document.write( "4th: (1-(3/365)) = (362/365 \n" ); document.write( "... \n" ); document.write( "8th: (1-(7/365)) = (358/365) \n" ); document.write( "---- \n" ); document.write( "P(no 2 of 8 have the same birthday) = [1(364)(363)(362)...(358)]/365^7 \n" ); document.write( "------- \n" ); document.write( "= 0.9257 \n" ); document.write( "---- \n" ); document.write( "P(2 have the same birthday) = 1 - 0.9257 = 0.0743 \n" ); document.write( "==================================================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " \n" ); document.write( " |