document.write( "Question 510357: a boat owner mixes together oil and gasoline to make 12 gallons of fuel for 8$ per gallon. Oil cost $15 per gallon and gasoline cost $3 per gallon. hOW MANY GALLONS OF EACH SHOULD USED???
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Algebra.Com's Answer #341811 by Maths68(1474)\"\" \"About 
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Let
\n" ); document.write( "Oil = x gallons
\n" ); document.write( "Gasoline = y gallons
\n" ); document.write( "Total cost of oil = 15x
\n" ); document.write( "Total cost of Gasoline = 3y
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\n" ); document.write( "Given
\n" ); document.write( "Oil Quantity + Gasoline Quantity = Mixture Quantity
\n" ); document.write( "x+y=12
\n" ); document.write( "x=12-y ...............(1)
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\n" ); document.write( "Total Cost of Oil + Total cost of Gasoline = Total Cost of Mixture
\n" ); document.write( "15x+3y=12*8
\n" ); document.write( "15x+3y=96 ..............(2)
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\n" ); document.write( "Put the value of x from (1) to (2)\r
\n" ); document.write( "\n" ); document.write( "15(12-y)+3y=96
\n" ); document.write( "180-15y+3y=96
\n" ); document.write( "-12y=96-180
\n" ); document.write( "-12y=-84
\n" ); document.write( "-12y/-12=-84/-12
\n" ); document.write( "-12y/-12=-84/-12
\n" ); document.write( "y=7\r
\n" ); document.write( "\n" ); document.write( "Put the value of x in (1)
\n" ); document.write( "x=12-y
\n" ); document.write( "x=12-7
\n" ); document.write( "x=5
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\n" ); document.write( "Oil = x = 5 gallons
\n" ); document.write( "Gasoline = y = 7 gallons
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\n" ); document.write( "Check
\n" ); document.write( "5*15 + 7*3 = 12*8
\n" ); document.write( "75+21=96
\n" ); document.write( "96=96
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