document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=510304>Question 510304</A>: <I><SPAN STYLE=\"word-break: break-all;\"> chemical is 60% acid and chemical B is 36% acid. How much of each should be mixed together to get 120oz of a chemical that is 52% acid? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #341787 by </B><A HREF=/tutors/aboutme.mpl?userid=oberobic><B>oberobic(2304)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=oberobic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=341787\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> With mixture problems, you need to keep track of how much 'pure' stuff you have or need.<BR>\n" );
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document.write( "120 oz. of a 52% solution means you need to have .52*120 = 62.4 oz of 'pure' acid in the 120 oz.<BR>\n" );
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document.write( "You will combine an unknown amount of one solution, 'x' with another amount to have 120 oz.<BR>\n" );
document.write( "So we can use x' and '120-x' as the two volumes.<BR>\n" );
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document.write( "The combined solutions are defined by the following equation.<BR>\n" );
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document.write( "60%*x + 36%(120-x) = 52%*120<BR>\n" );
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document.write( "Solve it.<BR>\n" );
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document.write( ".60x + .36(120-x) = .52*120<BR>\n" );
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document.write( "multiply by 100 to eliminate decimals<BR>\n" );
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document.write( "60x + 36(120-x) = 52*120<BR>\n" );
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document.write( "60x +4320 -36x = 6240<BR>\n" );
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document.write( "24x = 6240 -4320<BR>\n" );
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document.write( "24x = 1920<BR>\n" );
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document.write( "x = 80 oz<BR>\n" );
document.write( "120-x = 40 oz<BR>\n" );
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document.write( "Answer:  Combine 80 oz. of 60% solution and 40 oz. of 36% solution.<BR>\n" );
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document.write( "Check to be sure the answer is right.<BR>\n" );
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document.write( "60%(80 oz) = 48 oz of 'pure' acid <BR>\n" );
document.write( "36%(40 oz) = 14.4 oz of 'pure' acid<BR>\n" );
document.write( "48 + 14.4 = 62.4 oz. of 'pure' acid in the 120 oz., which is what we need to achieve 52%<BR>\n" );
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document.write( "Done.<BR>\n" );
document.write( " </SPAN>\n" );
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