document.write( "Question 51243: 2x-3=-11-2x. This is what I have done so far.\r
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Algebra.Com's Answer #34178 by AnlytcPhil(1806)\"\" \"About 
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2x-3=-11-2x. This is what I have done so far.\r\n" );
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document.write( "2x=2x-3=-11-2x+2x\r\n" );
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document.write( "When solving an equation, it is always a mistake to put\r\n" );
document.write( "two equal signs on the same line. Only put ONE equal \r\n" );
document.write( "sign to a line.\r\n" );
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document.write( "Rules:\r\n" );
document.write( "1. To get rid of a term on one side of an equation, add \r\n" );
document.write( "its opposite to BOTH sides of the equation\r\n" );
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document.write( "2.  Get rid of all terms on the LEFT side which DO NOT\r\n" );
document.write( "contain x, and leave all terms which DO contain x.\r\n" );
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document.write( "3.  Get rid of all terms on the RIGHT side which DO \r\n" );
document.write( "contain x, and leave all terms which DO NOT contain x.\r\n" );
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document.write( "4.  When only the unknown letter and its \r\n" );
document.write( "numerical coefficient, such as 5x or -3y, are on the \r\n" );
document.write( "left side, and the variable does not appear on the\r\n" );
document.write( "right side, then get rid of the coefficient of x by\r\n" );
document.write( "dividing both sides by that numerical coefficient.;\r\n" );
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document.write( "We are given\r\n" );
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document.write( "          2x - 3 = -11\r\n" );
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document.write( "The 2x contains x and is on the LEFT, so by rule 2,\r\n" );
document.write( "we leave it there.\r\n" );
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document.write( "The -3 does not contain x and is on the LEFT, so by\r\n" );
document.write( "rule 2, we get rid of it.  To do this we use rule 1\r\n" );
document.write( "and add its opposite, which is +3, to both sides. So\r\n" );
document.write( "we write on the second line:\r\n" );
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document.write( "      2x - 3 + 3 = -11 + 3\r\n" );
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document.write( "Then we simplify. The -3 and the 3 add to 0 so we just\r\n" );
document.write( "have 2x on the left. We combine the -11 and the 3 on\r\n" );
document.write( "the right and get -8.  So we write on the third line:  \r\n" );
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document.write( "              2x = -8\r\n" );
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document.write( "Now by rule 4, we must get rid of the 2 coefficient by\r\n" );
document.write( "dividing both sides by 2, so we write on the fourth\r\n" );
document.write( "line:\r\n" );
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document.write( "             2x     -8\r\n" );
document.write( "            覧覧 = 覧覧\r\n" );
document.write( "              2      2\r\n" );
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document.write( "Now we do some canceling. The 2's cancel on the left.\r\n" );
document.write( "And the -8 divided by the 2 on the right gives -4\r\n" );
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document.write( "             1       4 \r\n" );
document.write( "             2x     -8\r\n" );
document.write( "            覧覧 = 覧覧\r\n" );
document.write( "              2      2               \r\n" );
document.write( "              1      1\r\n" );
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document.write( "Notice that the negative sign of the -8 did not cancel \r\n" );
document.write( "on the right, so it's still there and we get -4 on the \r\n" );
document.write( "right, so we write on the last line:\r\n" );
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document.write( "               x = -4\r\n" );
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document.write( "Edwin
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