document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=510279>Question 510279</A>: <I><SPAN STYLE=\"word-break: break-all;\"> One number is seven more than twice another. If their sum is decreased by nine, the result is thirteen. Find the numbers. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #341772 by </B><A HREF=/tutors/aboutme.mpl?userid=algebrahouse.com><B>algebrahouse.com(1659)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=algebrahouse.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=algebrahouse.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=341772\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> \"One number is seven more than twice another. If their sum is decreased by nine, the result is thirteen. Find the numbers.\"\r<BR>\n" );
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document.write( "x = one number<BR>\n" );
document.write( "2x + 7 = other number {one number is seven more than twice another}\r<BR>\n" );
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document.write( "x + 2x + 7 - 9 = 13 {if their sum is decreased by 9, the result is 13}<BR>\n" );
document.write( "3x - 2 = 13 {combined like terms}<BR>\n" );
document.write( "3x = 15 {added 2 to both sides}<BR>\n" );
document.write( "x = 5 {divided both sides by 3}<BR>\n" );
document.write( "2x + 7 = 17 {substituted 5, in for x, into 2x + 7}\r<BR>\n" );
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document.write( "5 and 17 are the two numbers<BR>\n" );
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