document.write( "Question 510255: If the product of 2 consecutive integers is 45 more than 5 times the first integer. What are the 2 integers? \n" ); document.write( "
Algebra.Com's Answer #341762 by mananth(16949)\"\" \"About 
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one integer be x
\n" ); document.write( "other will be (x+1)\r
\n" ); document.write( "\n" ); document.write( "x(x+1)=5x+45
\n" ); document.write( "x^2+x=5x+45
\n" ); document.write( "x^2-5x+x-45=0
\n" ); document.write( "x^2-4x-45=0
\n" ); document.write( "x^2-9x+5x-45=0
\n" ); document.write( "x(x-9)+5(x-9)=0
\n" ); document.write( "(x-9)(x+5)=0\r
\n" ); document.write( "\n" ); document.write( "x=9 OR -5\r
\n" ); document.write( "\n" ); document.write( "The integers are
\n" ); document.write( "(9,10) , (-5,-4)
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